Launching Flame project on a command line

Flame Flame Questions
1

Hello. I’m trying to launch Flame on a mac via the command name and by passing the project settings page by specifying the user and project as it describes in the docs.

https://help.autodesk.com/view/FLAME/2024/ENU/?guid=Flame_API_Python_Hooks_Reference_Python_Hooks_Tips_html

However I’ve tried every combination and the project settings page still appears:

/opt/Autodesk/.flamefamily_2024.2.2/bin/flame.app/Contents/MacOS/flame -J --start-project=the_project_name -U --start-user=my_user_name

/opt/Autodesk/.flamefamily_2024.2.2/bin/flame.app/Contents/MacOS/flame -J the_project_name -U my_user_name

/opt/Autodesk/.flamefamily_2024.2.2/bin/flame.app/Contents/MacOS/flame --start-project=the_project_name --start-user=my_user_name

Is there anything I am doing wrong? Many thanks in advance.

Thanks

Steve

2

To see what your options are, I’d try:
/opt/Autodesk/flame_2024.2/bin/./startApplication --help

or:
/opt/Autodesk/flame_2024.2/bin/./startApplication --start-project=PROJECT --start-workspace=WORKSPACE

Specifying a user probably won’t work anymore:
--start-user=STRING Deprecated argument, no longer used

3

I’m not sure the project settings page is bypassed. For instance, if I want to start the application with the project named LostPlanet and the user to be ytf, the exact command line would be
/opt/Autodesk/flame_2024.2.1/bin/startApplication -J LostPlanet -U ytf
This sets the project settings page to the proper project and user, but I still need to hit the Start button.

4

I think if you specify a workspace with -W=WORKSPACE or --start-workspace=WORKSPACE it will bypass that screen.

5

Here’s one of the automatically generated launchers for LOGIK-PROJEKT - it works with flame 2025+

  /opt/Autodesk/flame_2025.2.1/bin/startFlame \
   -J 1010_abc_def_2025_2_1_delta \
   --start-workspace="delta" --create-workspace \
   create_projekt_layout.py
3 Likes
6

Thank you all for the suggestions. I found this works and bypasses the project settings screen which is what I wanted. This is the syntax I used:

/opt/Autodesk/.flamefamily_2024.2.2/bin/flame.app/Contents/MacOS/startApp --start-project=my_new_project --start-user=steveo --start-workspace="Workspace"

Thanks very much.

Steve

3 Likes
7

I tested right know and it works!!. First time I can bypass the start button in selection project window, and I have been trying for a long time.

Note: For 2025, the flag start user is not needed.

1 Like
8

I know there are a lot of folks who know a lot more about this than I, but I thought that starting flame with /flame instead of /startApplication left some services off.

1 Like
9

To aid in all of this I typically set an alias in my shell to start flame.

put this in your .zshrc file

alias flame=‘/opt/Autodesk/flame_2025.2.1/bin/./startApplication’;

10

To clarify, I used ./startApplication (I’m on linux)

11

and not meaning to nitpick, but I don’t think you need the ./ since you are already specifying the path.

2 Likes
12

I didn’t realize that. i’ve been using the same basic alias for years

13

"Hey Siri, start flame..."

"I'm sorry, would you like me to search the internet for flame?"

14

The ‘.’ stands for ‘start path at current folder’. It’s the companion to ‘/’ which says ‘start path at root’. You use one or the other.

So you do need to use the ‘.’ if you just type ./StartApplication and this folder you’re in is not part of the $PATH environment variable.